\(\left(2x+1\right)^3=343\)
\(\left(2x+1\right)^3=7^3\)
\(\Rightarrow2x+1=7\)
\(2x=7-1\)
\(2x=6\)
\(x=6:2\)
\(x=3\)
Vậy x = 3
Ta có: (2x + 1)3 = 343
\(\Leftrightarrow\)(2x + 1)3 = 73
\(\Leftrightarrow\)2x + 1 = 7
\(\Leftrightarrow\)2x = 7 - 1 = 6
\(\Leftrightarrow\)x = 6: 2 = 3
Vay x = 3
ta có
(2x+1)^3=343
<=>(2x+1)^3=7^3
=>2x+1=7
=>x=4