`2(x-1)+3(x-1)=0`
`=>(x-1)(2+3)=0`
`=>(x-1).5=0`
`=>x-1=0`
`=>x=1`
`=> 5(x-1) = 0`
`=> x - 1 = 0`
`=> x = 1`
`2(x-1) + 3 (x-1) = 0 `
` (2 + 3).(x-1) = 0`
`5(x-1) = 0`
`=> x - 1 = 0`
`=> x = 1`
Vậy `x = 1`
`#BaoL i n h`
`2(x-1)+3(x-1)=0`
`=>(2+3)(x-1)=0`
`=>5(x-1)=0`
`=>x-1=0`
`=>x=1`
Vậy `x=1`