Question

tìm x biết : x(x-1)-(x-2)x=0   giúp mik với

Answer 1

\(x\left(x-1\right)-\left(x-2\right)x=0\\ \Leftrightarrow x^2-x-x^2-2x=0\\ \Leftrightarrow1x=0\\ \Leftrightarrow x=0\)

Answer 2

`x.(x-1) - (x-2).x = 0`

`x^2 -x - x^2 -2x = 0`

`(x^2 - x^2) + (-x + 2x) = 0`

`0 + (-x+2x) = 0`

`1x = 0`

`=> x = 0 : 1`

`x = 1`

Answer 3

\(x\left(x-1\right)-\left(x-2\right)x=0\)

\(\Leftrightarrow x^2-x-\left(x+2\right).x=0\)

\(\Leftrightarrow x^2-x-\left(x^2+2x\right)=0\)

\(\Leftrightarrow x^2-x-x^2-2x=0\)

\(\Leftrightarrow-x-2x=0\)

\(\Leftrightarrow-3x=0\)

\(\Leftrightarrow x=0\)

Answer 4

`x(x-1) - (x-2)x=0`

`=> x^2 - x - x^2 - 2x = 0`

`=> (x^2 - x^2) + (-x + 2x) = 0`

`=> 1x=0`

`=> x  = 0 : 1`

`=>x = 0`