\(\left(x^2-9\right)^2-\left(x-3\right)^2=0\)
\(\Leftrightarrow\left(x-3\right)^2\cdot\left(x+2\right)\left(x+4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-2\\x=-4\end{matrix}\right.\)
Câu 2.(1,5 điểm) Tìm x, biết:
a) 5x(x2 – 9) = 0. b) 3(x+3) - x2 - 3x =0. c) x2 – 9x – 10 = 0
Tìm x biết ( x - 3 ) ( x 2 + 3 x + 9 ) + x ( x + 2 ) ( 2 - x ) = 0 .
Tìm x, biết:
a) 3x(x - 1) + x - 1 = 0;
b) (x - 2)( x 2 + 2x + 7) + 2( x 2 - 4) - 5(x - 2) = 0;
c) ( 2 x - 1 ) 2 - 25 = 0;
d) x 3 + 27 + (x + 3)(x - 9) = 0.
Tìm x, biết:
a) ( x + 3 ) 2 + (4 - x)(x + 4) = 1;
b) (2 - x) 3 +(3 +x)(9 - 3x + x 2 ) + 6x(1 - x) = 17;
c) x 4 - 2 x 2 +1 = 0.
Bài 11: Tìm x biết:
a) (x+2)(x2-2x+4) - x(x2+2) =15
b) (x+3)2 –x(3x+1)2 +(2x+1)(4x2 -2x+1) =28
c) (x2-1)3 - (x4+x2+1)(x2-1) = 0
d) (x-2)3 –(x-3)(x2 + 3x+9) +6(x+1)2 = 49
Tìm x biết :
a, (x-2).(x2 +2x +7) +2.( x2-4) -5 .(x-2) =0
b, 4x2 -25 -(2x-5) .(2x+7) =0
c, x3 +27 + (x+3) .(x-9)=0
Bài 1.Tìm x biết
a) ( x - 3 )( x2+ 3x + 9 ) + x( x + 2 )( 2 - x ) = 0.
b) ( x + 1 )3- ( x - 1 )3- 6( x - 1 )2 = - 10.
Tìm x:
a)x.(x-1)-(x-2)2=2
b)x2-9=(x-3).(6-x)
c)x2-x-6=0
Tìm x:
a)x.(x-1)-(x-2)2=2
b)x2-9=(x-3).(6-x)
c)x2-x-6=0
