tim x biet: (x+1)+(x+2)+(x+3)+...(x+2013) = 0
Tim cac so nguyen x biet rang:
a,x+(x+1)+(x+2) +...+19+20=20
b,x+(x+1)+(x+2)+...+2013+2014=2014
Tim x biet:
\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+......+\frac{2}{x\left(x+1\right)}=\frac{2011}{2013}\)
tim x biet x(x-1)=0
(x-1).(x+2)=0
tim x biet(x+1)+(x+2)+...+(x+2017)=0
tim x biet (x+1)+(x+2)+.........+(x+2017)=0
tim x,y,z biet x-y=2011;y-z=-2011;z+x=2013
tim x,y,z biet x-y=2011,y-z=-2012,z+x=2013