\(\dfrac{1}{4}-\left(2\cdot x\cdot\dfrac{1}{2}\right)^2=0\)
\(\left(2x\cdot\dfrac{1}{2}\right)^2=\dfrac{1}{4}-0\)
\(\left(2\cdot x\cdot\dfrac{1}{2}\right)^2=\dfrac{1}{4}\)
`->`\(\left(2\cdot x\cdot\dfrac{1}{2}\right)^2=\left(\pm\dfrac{1}{2}\right)^2\)
`->`\(\left[{}\begin{matrix}2\cdot x\cdot\dfrac{1}{2}=\dfrac{1}{2}\\2\cdot x\cdot\dfrac{1}{2}=-\dfrac{1}{2}\end{matrix}\right.\)
`->`\(\left[{}\begin{matrix}2x=\dfrac{1}{2}\div\dfrac{1}{2}\\2x=-\dfrac{1}{2}\div\dfrac{1}{2}\end{matrix}\right.\)
`->`\(\left[{}\begin{matrix}2x=1\\2x=-1\end{matrix}\right.\)
`->`\(\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-\dfrac{1}{2}\end{matrix}\right.\)
Vậy, `x=1/2` hoặc `x=-1/2.`
