\(\left(x+\frac{1}{2}\right).\left(x-\frac{3}{4}\right)=0\)
TH1:
\(x+\frac{1}{2}=0\)
=> x = \(\frac{-1}{2}\)
TH2:
\(x-\frac{3}{4}=0\)
=> x = \(\frac{3}{4}\)
Tim x biet : 20 . 2^x + 1 = 10.4^2 + 1
Tim x : ( 4-x:2)^3 - 1 = 2 . (2^3 - 5 : 2^0 )
tim x thuoc Z biet :
(x-1)^2 =(x-3)^4
HELP ME:0!!
tim x thuoc z biet
(x-1)(x-3)=-5
(x+1)(x+4)=0
(x^2-4)(x^2-19)<0
tim so nguyen x biet
(x - 4)(x + 3)> 0
(x - 2)(x + 1)< 0
1,tim cac so nguyen x,y biet: -2/x=y/3 va x<0<y
2, Tim cac so nguyen x,y biet:x-3/y-2=3/2 va x-y=4
tim so nguyen x biet
(x + 3)(x - 1)<0
(x - 4)(x + 3)>0
Tim x , biet
(x^2+1).(x^2-4)=0
1, tim x biet
a, (2-x).(x-3).(x+4)=0
b. (x-7).(x+3)<0
xin cac ban gup minh chieu nay minh hoc roi nhe !
