lxl+1/2=3/4
=>lxl=3/4-1/2=1/4
=> x=1/4 hoặc x=-1/4
\(TH1:x\ge0\)
\(\Rightarrow x+\frac{1}{2}=\frac{3}{4}\)
\(\Rightarrow x=\frac{3}{4}-\frac{1}{2}\)
\(\Rightarrow x=\frac{1}{4}\)
\(TH2:x< 0\)
\(\Rightarrow-x+\frac{1}{2}=\frac{3}{4}\)
\(\Rightarrow-x=\frac{3}{4}-\frac{1}{2}\)
\(\Rightarrow x=-\frac{1}{4}\)