\(\left(x+5\right)+\left(x+10\right)+...+\left(x+60\right)=474\)
\(\left(x+x+...+x\right)+\left(\frac{\left(60+5\right)\left[\left(60-5\right):5+1\right]}{2}\right)=474\)
\(12x+390=474\)
\(12x=84\)
\(x=7\)
\(\left(x+5\right)+\left(x+10\right)+\left(x+15\right)+...+\left(x+60\right)=474\)
\(x+5+x+10+x+15+...+x+60=474\)
\(x+x+x+...+x+5+10+15+...+60=474\)
12 số x
\(12\times x+\left(60+5\right)\times12\div2=474\)
\(12\times x+390=474\)
\(12\times x=474-390\)
\(12\times x=84\)
\(x=84\div12\)
\(x=7\)
Vậy \(x=7\).
7/5-X=12/10