Question

tìm x biết : (x-1)^2-(2-3x)^2 giúp mk vs mn

Answer 1

\(\left[{}\begin{matrix}x-1-2+3x=0\\x-1+2-3x=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}4x-3=0\\-2x+1=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=\dfrac{1}{2}\end{matrix}\right.\)

Answer 2

\(\left(3x-2\right)^2-\left(x-1\right)^2=0\)

\(\Leftrightarrow\left(3x-2-x+1\right)\left(3x-2+x-1\right)=0\)

\(\Leftrightarrow\left(2x-1\right)\left(4x-3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=\dfrac{3}{4}\end{matrix}\right.\)