Ta có: \(\left|4x-1\right|=\left|x+2\right|\)
\(\Leftrightarrow\left[{}\begin{matrix}4x-1=x+2\\4x-1=-x-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=3\\5x=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{1}{5}\end{matrix}\right.\)