Question

Tìm x biết \(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+44+}{325}+\frac{x+5}{324}=-4\). Ghi cách giải nhá !

Answer 1

== bài dễ , cậu giỏi sao giờ nằm viện mà ======== :v

Answer 2

Ta có:

\(\left(\frac{x+2}{327}+1\right)+\left(\frac{x+3}{326}+1\right)+\left(\frac{x+4}{325}+1\right)+\left(\frac{x+5}{324}+1\right)=\left(-4\right)+1+1+1+1\)

\(\Rightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}=0\)

\(\Rightarrow\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}\right)=0\)

Mà \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}\ne0\)

\(\Rightarrow x+329=0\)

\(\Rightarrow x=-329\)

Answer 3

Ta có : \(\frac{x+329-327}{327}+\frac{x+329-326}{326}+\frac{x+329-325}{325}+\frac{x+329-324}{324}\)

\(\Rightarrow\frac{x+329}{327}-1+\frac{x+329}{326}-1+\frac{x+329}{325}-1+\frac{x+329}{324}-1=-4\)

\(\Leftrightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}=0\)

\(\Rightarrow\left(x+329\right).\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}\right)=0\)

\(\Rightarrow x+329=0\Rightarrow x=-329\)

 

Answer 4

sử dụng máy tính đk mà

 

Answer 5

Đoạn x+44 hình như ko hợp lí lắm

Answer 6

hìh như đề sai . x+4 mới đúng

Answer 7

Dung lm đúng rùi đó