\(a.\)
\(2\left(x+5\right)-x^2-5x=0\)
\(\Leftrightarrow2x+10-x^2-5x=0\)
\(\Leftrightarrow-x^2-3x+10=0\)
\(\Leftrightarrow-x^2+2x-5x+10=0\)
\(\Leftrightarrow x\left(2-x\right)+5\left(2-x\right)=0\)
\(\Leftrightarrow\left(2-x\right)\left(x+5\right)=0\)
\(\Leftrightarrow^{2-x=0}_{x+5=0}\Leftrightarrow^{x=2}_{x=-5}\)
Vậy, \(x\in\left\{-5;2\right\}\)