a) \(2x^2-4x=0\)
\(2x\left(x-2\right)=0\)
TH1:2x=0⇒x=0
TH2:x-2=0⇒x=2
\(a,\Leftrightarrow2x\left(x-2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\\ b,\Leftrightarrow\left(x+5\right)\left(x-3\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-5\\x=3\end{matrix}\right.\\ c,\Leftrightarrow2\left(x-4\right)-\left(x-4\right)=0\\ \Leftrightarrow x-4=0\Leftrightarrow x=4\)
2x(x - 2) = 0
2x = 0 hoặc x - 2 = 0
x = 0 hoặc x = 2
(x - 3)(x + 5) = 0
x - 3 = 0 hoặc x + 5 = 0
x = 3 hoặc x = -5
(x - 4)2 = 0
x = 4