Ta có: 4x2 - 12x + 9 = 0
=> (2x - 3)2 = 0
=> 2x - 3 = 0
=> x = 3/2
Vậy x = 3/2
\(4x^2-12x=-9\)
\(\Rightarrow\left(2x\right)^2-2.\left(3x\right)+9=0\)
\(\Rightarrow\left(2x\right)^2-2.\left(3x\right)+3^2=0\)
\(\Rightarrow\left(2x-3\right)^2=0\)
\(\Rightarrow2x-3=0\)
\(\Rightarrow2x=3\)
\(\Rightarrow x=\frac{3}{2}\)