Question

tìm x biết 

210:(2x-3)-20=10

 

Answer 1

$210:(2x-3)-20=10$

$=>210:(2x-3)=10+20$

$=>210:(2x-3)=30$

$=>2x-3=210:30$

$=>2x-3=7$

$=>2x=7+3$

$=>2x=10$

$=>x=10:2$

$=>x=5$

Answer 2

210 : (2x - 3 ) - 20 = 10

⇒ 210 : (2x - 3 ) = 30

⇒ 2x - 3 = 7

⇒ 2x = 10

⇒ x = 5 .

Vậy x = 5.

Answer 3

\(210:\left(2x-3\right)-20=10\) (ĐK: \(x\ne\dfrac{3}{2}\))

\(\Rightarrow210:\left(2x-3\right)=10+20\)

\(\Rightarrow210:\left(2x-3\right)=30\)

\(\Rightarrow2x-3=210:30\)

\(\Rightarrow2x-3=7\)

\(\Rightarrow2x=7+3\)

\(\Rightarrow x=\dfrac{10}{2}\)

\(\Rightarrow x=5\left(tm\right)\)

Answer 4

210:(2x-3)-20=10

=>210:(2x-3)=10+20=30

=>2x-3=210:30=70

=>2x=70+3=73

=>x=73:2=\(\dfrac{73}{2}\)

Answer 5

210:(2x-3)-20= 10

210:(2x-3)= 10+20

210:(2x-3)= 30

       (2x-3)= 210:30

       (2x-3)= 7

       2x-3= 7

       2x   = 7+3

       2x   = 10

         x   = 10:2

         x   = 5