a) Ta có: \(\left(x+2\right)\left(x^2-2x+4\right)=35\)
\(\Leftrightarrow x^3+8=35\)
\(\Leftrightarrow x^3=27\)
hay x=3
b) Ta có: \(\left(25x^2+5x+1\right)\left(5x-1\right)=-9\)
\(\Leftrightarrow125x^3-1=-9\)
\(\Leftrightarrow125x^3=-8\)
\(\Leftrightarrow x=-\dfrac{2}{5}\)