Question

Tìm X :

a) X : 0,(7) = 0,(32) : 2,(4)

b) 0,(17) : 2,(3) = X : 0,(3)

Answer 1

a) X : \(\frac{7}{9}=\frac{32}{99}:\left(2+\frac{4}{9}\right)\) => X : \(\frac{7}{9}=\frac{32}{99}:\frac{22}{9}\)=> X : \(\frac{7}{9}=\frac{64}{81}\) => X = \(\frac{64}{81}.\frac{7}{9}=\frac{64}{63}\)

b) \(\frac{17}{99}:\left(2+\frac{3}{9}\right)=X:\frac{3}{9}\)=> \(\frac{17}{99}:\frac{7}{3}=X:\frac{1}{3}\)=> \(\frac{17}{231}=X:\frac{1}{3}\)=> X = \(\frac{17}{231}.\frac{1}{3}=\frac{17}{693}\)

Vậy...

Answer 2

a, \(x=\frac{64}{63}\)

b, \(\frac{17}{693}\)
 

Answer 3

a)X:O,(7)=O,(32):2,(4)

X:O,(7)=32/99:0,(4)+2

X:0,(7)=32/99:4/9+2

X:0,(7)=128/891+2

X=1910/891.7/9

X=1,667290186

b)0,(17)/2,(3)=X/0,(3)

=>X=17/9.3/9:7/3

X=17/63