Question

 Tìm x

 a) [( 8x - 12 ) : 4] .3³=3⁶

 b) 41 - 2^x+1 = 9

Answer 1

\(a.\left[\left(8x-12\right):4\right]\cdot3^3=3^6\\ \left(8x-12\right):4=3^6:3^3\\ \left(8x-12\right):4=27\\ 8x-12=27\cdot4\\ 8x-12=108\\ 8x=108+12\\ 8x=120\\ x=15\\ b.41-2^{x+1}=9\\ 2^{x+1}=32\\ 2^{x+1}=2^5\\=> x+1=5\\ =>x=4\)

Answer 2

a,[(8x-12):4].3³=3⁶

(8x-12):4=3⁶:3³

(8x-12):4=3³

(8x-12):4=9

8x-12=9.4

8x-12=36

8x=36+12

8x=48

x=6

Vậy x=6

b,41-2^x+1=9

2^x+1=41-9

2^x+1=32

2^x+1=2⁵

^x+1=5

^x=5-1

^x=4

^{Vậy x=4}

^{Chúc bạn học tốt:33}

Answer 3

mình nhầm phép tính a

xin lỗi bạn

Answer 4

,[(8x-12):4].33=36

(8x-12):4=36:33

(8x-12):4=33

(8x-12):4=27

8x-12=27.4

8x-12=108

8x=108+12

8x=120

x=15

Vậy x=15