\(a)2\left(x+3\right)-x^2-3x=0\)
\(\Leftrightarrow2x+6-x^2-3x=0\)
\(\Leftrightarrow-x^2+2x-3x+6=0\)
\(\Leftrightarrow-x^2-x+6=0\)
\(\Leftrightarrow x^2+x-6=0\)
\(\Leftrightarrow x^2+3x-2x-6=0\)
\(\Leftrightarrow x\left(x+3\right)-2\left(x+3\right)=0\)
\(\Leftrightarrow\left(x+3\right)\left(x-2\right)=0\)
\(\Leftrightarrow x+3=0\) hoặc \(x-2=0\)
\(\Leftrightarrow x=-3\) hoặc \(x=2\)
\(b)4x^2-25-\left(2x-5\right)\left(2x+7\right)=0\)
\(=\left(2x-5\right)\left(2x+5\right)-\left(2x-5\right)\left(2x+7\right)=0\)
\(=\left(2x-5\right)\left(2x+5-2x-7\right)=0\)
\(=-2\left(2x-5\right)=0\)
\(=2x-5=0\Leftrightarrow x=\frac{5}{2}\)
Cảm ơn bạn rất nhiều