5(x-2) - x2 + 4 = 0
<=> 5(x-2) - (x2 - 4) = 0
<=> 5(x-2) - (x-2)(x+2) = 0
<=> (x-2)(5-x-2) = 0
<=> (x-2)(3-x) = 0
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\3-x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=3\end{matrix}\right.\)
Vậy \(x\in\left\{2;3\right\}\)