Question

Tìm x :

4^x+2 -5. 4^x =176

(4^x+2 là 4 mũ x cộng 2 )

Answer 1

\(4^{x+2}-5\cdot4^x=176\)

\(\Rightarrow4^x\cdot4^2-5\cdot4^x=176\)

\(\Rightarrow4^x\cdot\left(16-5\right)=176\)

\(\Rightarrow4^x\cdot11=176\)

\(\Rightarrow4^x=\dfrac{176}{11}\)

\(\Rightarrow4^x=16\)

\(\Rightarrow4^x=4^2\)

\(\Rightarrow x=2\)

Answer 2

\(4^{x+2}-5.4^x=176\)

\(=>4^x.4^2-5.4^x=176\)

\(=>4^x.\left(4^2-5\right)=176\)

\(=>4^x.\left(16-5\right)=176\)

\(=>4^x.11=176\)

\(=>4^x=176:11\)

\(=>4^x=16\)

\(=>4^x=4^2\)

\(=>x=2\)