\(3x\left(2x+3\right)-4x^2=-9\)
\(3x\left(2x+3\right)-4x^2+9=0\)
\(3x\left(2x+3\right)-\left[\left(2x\right)^2-3^2\right]=0\)
\(3x\left(2x+3\right)-\left(2x-3\right)\left(2x+3\right)=0\)
\(\left(2x+3\right)\left(3x-2x+3\right)=0\)
\(\left(2x+3\right)\left(x+3\right)=0\)
\(\orbr{\begin{cases}2x+3=0\\x+3=0\end{cases}}\)
\(\orbr{\begin{cases}x=\frac{-3}{2}\\x=-3\end{cases}}\)
Tìm x biết:
a, 16x² – 9(x + 1)²= 0
b, x2 (x – 1) – 4x2 + 8x – 4 = 0
c, x(2x – 3) – 2(3 – 2x) = 0
d, (x – 3)(x² + 3x + 9) – x(x + 2)(x – 2) = 1
e, 4x² + 4x – 6 = 2
f, 2x² + 7x + 3 = 0
Tìm x, biết:
a)(x+3)3-x(3x+1)2+(2x+1)(4x2-2x+1)-3x2=54
b)(x-3)3-(x-3)(x2+6x+9)+6(x+1)2+3x2=-33
tìm x thỏa mãn:
a) (x+2)(x+3)-(x-2)(x-5)=-4
b) (x+1)(x2-x+1)-x(x-3)(x+3)=8
c) 4x2-9=(3x+1)(2x-3)
d) (3x+1)2-4(x-1)2=0
Bài 1: Giải các phương trình dưới đây
1) x2 - 9 = (x - 3)(5x +2)
2) x3 - 1 = (x - 1)(x2 - 2x +16)
3) 4x2 (x - 1) - x + 1 = 0
4) x3 + 4x2 - 9x - 36 = 0
5) (3x + 5)2 = (x - 1)2
6) 9 (2x + 1)2 = 4 (x - 5)2
7) x2 + 2x = 15
8) x4 + 5x3 + 4x2 = 0
9) (x2 - 4) - (x - 2)(3 - 2x) = 0
10) (3x + 2)(x2 - 1) = (9x2 - 4) (x + 1)
11) (3x - 1)(x2 + 2) = (3x - 1)(7x - 10)
12) (2x2 + 1) (4x - 3) = (x - 12)(2x2 + 1)
Rút gọn biểu thức:
a) (x + 2)(x – 2) – (x + 1)2
b) (2x – 1)(4x2 + 2x + 1) – (2x + 1)( 4x2 – 2x + 1)
3. Tìm x biết:
a) (x + 2)(x2 – 2x + 4) – x(x2 – 2) = 15
b) (x – 1)3 – x(x2 – 3x – 4) = 13
thanks
Các bạn giúp mình với !!!
a,(3x-1)2+(x+3)2-10(x+1)(x-1)=0
b,(x+3)3+(2x+1)(4x2-2x+1)-9x2(x+1)=54
c,(x-3)3-(x-3)(x2+3x+9)+9(x+1)2=-33
(2x-3)2+4x2-9=(2x-3)(3x+5)
Rút gọn biểu thức.
a)A=(x-3)(x2+3x+9)-(x3+3)
b)B=(2x+1)(4x2-2x+1)-8(x+1/2)(x2-1/2x+1/4)
Rút gọn các biểu thức sau:
a) (x + 3)(x2 – 3x + 9) – (54 + x3)
b) (2x + y)(4x2 – 2xy + y2) – (2x – y)(4x2 + 2xy + y2)
Tìm x:
a, x(2x – 3) – 2(3 – 2x) = 0
b, (x – 3)(x2 + 3x + 9) – x(x + 2)(x – 2) = 1
c, 4x2 + 4x – 6 = 2
d, 2x2 + 7x + 3 = 0
