: `a) x : 3/8 = 1/6`
`=>x=1/6xx3/8`
`=>x=1/16`
Vậy `x=1/16` `
` b) 3/7xx x = 4/3 + 2/3`
`=>3/7xx x=6/3=2`
`=>x=2:3/7`
`=>x=14/3`
Vậy `x=14/3`
`a) x : 3/8 = 1/6`
`=>x=1/6xx3/8`
`=>x=1/16`
Vậy `x=1/16`
` b) 3/7xx x = 4/3 + 2/3`
`=>3/7xx x=6/3=2`
`=>x=2:3/7`
`=>x=14/3`
Vậy `x=14/3`
x : 3/8=1/6
x= 1/6 x 3/8
x= 3/48
B) 3/7 : x = 4/3+2/3
3/7 : x = 6/3
x= 6/3 x 3/7
=18/21
Ta có: \(\dfrac{3}{7}\cdot x=\dfrac{4}{3}+\dfrac{2}{3}\)
\(\Leftrightarrow x\cdot\dfrac{3}{7}=2\)
hay \(x=\dfrac{14}{3}\)
Vậy: \(x=\dfrac{14}{3}\)