2x(x^2-1)+x(1-3x-2x^2)=-x-27
2x3-2x+x-3x2-2x3=-x-27
-3x2-x =-x-27
-3x2-x+x =27
-3x2 =27
x2 =9
=>x=9 hoặc x=-9
2x(x^2-1)+x(1-3x-2x^2)=-x-27
2x3-2x+x-3x2-2x3=-x-27
-3x2-x =-x-27
-3x2-x+x =27
-3x2 =27
x2 =9
=>x=9 hoặc x=-9
Tìm x:
a) (2x - 1) (x^2 - x + 1) = 2x^3 - 3x^2 + 2
b) (x + 1) (x^2 + 2x + 4) - x^3 - 3x^2 + 16 = 0
c) (x + 1) (x + 2) (x + 5) - x^3 - 8x^2 = 27
Tìm X
A, (X+1)(X+2)(X+5) - X^2(X+8)=27
B, 1/4 X^2-(1/2X-4)1/2X=-14
C, 3(1-4X)(X-1)+4(3X-2)(X+3)=-27
D,(X+3)(X^2-3X+9) - X(X-1)(X+1)=27
Tìm x biết
a) 3x(2x+3)-(2x+5)(3x-2)=8
b) (3x-4)(2x+1)-(6x+5)(x-3)=3
c) 2(3x-1)(2x+5)-6(2x-1)(x+2)= - 6
d) 3xy(x+y)-(x+y)(x2+y2+2xy)+y3=27
Bài 1 : Phân tích đa thức thành nhân tử
a) 5x^2y-20xy^2
b) 1-8x+16x^2-y^2
c) 4x-4-x^2
d) x^3-2x^2+x-xy^2
e)27-3x^2
f) 2x^2+4x+2-2y^2
Bài 2: tìm x, biết
a) x^2(x-2023)-2023+x=0
b) -x(x-4)+(2x^3-4x^2-9x):x=0
c) x^2+2x-3x-6=0
d) 3x(x-10)-2x+20=0
a)9x2 – 49 = 0
b)(x – 1)(x + 2) – x – 2 = 0
c)(4x + 1)(x - 2) - (2x -3)(2x + 1) = 7
d)x(3x + 2) + (x + 1)2 – (2x – 5)(2x + 5) = 0
e)(x + 3)(x2 – 3x + 9) –x(x – 1)(x + 1) – 27 = 0
f)(4x-3)^2-3x(3-4x)=0
Tìm x:
a) 4(x+3)(3x-2)-3(x-1)(4x-1)= -27
b) 4x(2x^2-1)+27=(4x^2+6x9)(2x+3)
Help !!
Bài 1: tìm x
1, 2x(3x-1)+1-3x=0
2, x\(^2\)(2x-3)+12-8x=0
3, 25(x-1)\(^2\)-4=0
4, 25x\(^2\)-10x+1=0
5, -4x\(^2\)+\(\dfrac{1}{9}\)=0
6, (x-1)\(^3\)=8
7, (2x-1)\(^3\)+27=0
8, 125+\(\dfrac{1}{8}\)(x-1)\(^3\)=0
Tìm x, biết:
a) 3x(x - 1) + x - 1 = 0;
b) (x - 2)( x 2 + 2x + 7) + 2( x 2 - 4) - 5(x - 2) = 0;
c) ( 2 x - 1 ) 2 - 25 = 0;
d) x 3 + 27 + (x + 3)(x - 9) = 0.
Bài 1 : chứng minh rằng các biểu thức sau đây không phụ thuộc vào x a,A=(3x+7)(2x+3)-(2x+3)-(3x-5)(2x+11) b,B=(x^2-2)(x^2+x-1)-x(x^3+x^2-3x-2) Bài 2:Tìm x biết: a,6x(5x+3)+3x(1-10x)=7 b,(3x-3)(5-21x)+(7x+4)(9x-5)=44 c,(x+1)(x+2)(x+5)-x^2(x+8)=27 d,(2x-1)(3-x)+(x-2)(x+3)=(1-x)(x+2) Bài 3 Tính a,(2x+3)^3 b,(x-3y)^3 c.(x+4)(x^2-4x+16) d,(1/3x+2y)(1/9x^2-2/3xy+4y) e,(x-3y)(x2+3xy+9y^2)