=>29/7x-1=22/7
=>29/7x=29/7
hay x=1
\(\left(\dfrac{29x}{7}-1\right)-3=\dfrac{1}{7}\)
\(\dfrac{29x}{7}-1=\dfrac{1}{7}+3\)
\(\dfrac{29x}{7}-1=\dfrac{22}{7}\)
\(\dfrac{29x}{7}=\dfrac{22}{7}+1\)
\(\dfrac{29x}{7}=\dfrac{29}{7}\)
\(29.x:7=\dfrac{29}{7}\)
\(29.x=\dfrac{29}{7}\times7\)
\(29.x=29\)
\(x=29:29=1\)