Question

Tìm x: 230+[2^2+(x-5)^2]=315×2021^0

Answer 1

230 + [2² + (x - 5)²] = 315 . 2021⁰

230 + 4 + (x - 5)² = 315.1

234 + (x - 5)² = 315

(x - 5)² = 315 - 234

(x - 5)² = 81

x - 5 = 9 hoặc x - 5 = -9

*) x - 5 = 9

x = 9 + 5

x = 14

*) x - 5 = -9

x = -9 + 5

x = -4

Vậy x = -4; x = 14

Answer 2

Cứucứu

Answer 3

\(230+\left[2^2+\left(x-5\right)^2\right]=315\times2021^0\\ 230+\left[4+\left(x-5\right)^2\right]=315\times1\\ 230+\left[4+\left(x-5\right)^2\right]=315\\ 4+\left(x-5\right)^2=85\\ \left(x-5\right)^2=81\\ \left(x-5\right)^2=9^2\\ x-5=9\\ x=14.\)