2: \(\Leftrightarrow3^x=3^7\)
=>x=7
4: \(\Leftrightarrow2^x=32\)
=>x=5
6: \(\Leftrightarrow2^{x+1}=32\)
=>x+1=5
=>x=4
8: \(\Leftrightarrow3^x\cdot2=18\)
=>3^x=9
=>x=2
10: \(\Leftrightarrow x\left(x^{2021}-1\right)=0\)
=>x=0 hoặc x=1
2) 3².3^x = 3⁹
3^x = 3⁹ : 3²
3^x = 3⁷
x = 7
4) 2^x . 8 = 256
2^x = 256 : 8
2^x = 32
2^x = 2⁵
x = 5
6) 2.2^x - 14 = 18
2.2^x = 18 + 14
2.2^x = 32
2^x = 32 : 2
2^x = 16
2^x = 2⁴
x = 4
8) 3^x . 2 + 15 = 33
3^x . 2 = 33 - 15
3^x . 2 = 18
3^x = 18 : 2
3^x = 9
3^x = 3²
x = 2
10) x²⁰²² = x
x²⁰²² - x = 0
x(x²⁰²¹ - 1) = 0
x = 0 hoặc x²⁰²¹ - 1 = 0
*) x²⁰²¹ - 1 = 0
x²⁰²¹ = 1
x = 1
Vậy x = 0; x = 1
