Question

tìm số tự nhiên x ,biết :    \(\dfrac{1}{3}\) < \(\dfrac{x}{2}\) < \(\dfrac{2}{3}\)

Answer 1

\(\dfrac{1}{3}< \dfrac{1}{2}< \dfrac{2}{3}\)

Answer 2

$\frac{1}{3}$< $\frac{x}{2}$< $\frac{2}{3}$

$\Rightarrow$$\frac{2}{6}$< $\frac{x\times 3}{6}$< $\frac{4}{6}$

$\Rightarrow$ 2 < x $\times$3 < 4

$\Rightarrow$x $\times$3 = 3

x = 3 $÷$3

x = 1

Answer 3

\(\dfrac{1}{3}< \dfrac{x}{2}< \dfrac{2}{3}\)

->  \(\dfrac{2}{6}< \dfrac{2x}{6}< \dfrac{4}{6}\)

-> \(2< 2x< 4\)

-> \(1< x< 2\) 

Vậy x nằm trong khoảng 1 < x < 2

Answer 4

Tham khảo e nhé!
1

$\frac{3}{}$< $\frac{x}{2}$< $\frac{2}{3}$

$\Rightarrow$$\frac{2}{6}$< $\frac{x\times 3}{6}$< $\frac{4}{6}$

$\Rightarrow$ 2 < x $\times$3 < 4

$\Rightarrow$x $\times$3 = 3

x = 3 $÷$3

x = 1

Vậy x = 1