a) \(2^n:4=16\)
\(2^n:2^2=2^4\)
\(=>n-2=4\)
\(=>n=6\)
b) \(3^n:3^2=243\)
\(3^n:3^2=3^5\)
\(=>n-2=5\)
\(=>n=7\)
vay \(n=7\)
c) \(2^n-64=2^6\)
\(2^n-2^6=2^6\)
\(2^n=2^6+2^6\)
\(2^n=128\)
\(2^n=2^7\)
\(=>n=7\)
vay \(n=7\)
A/ => 16.4=2n
=> 2n =64
2n=26
=> n = 6
B/ 3n=243.32
3n=35.32
3n=37
Vậy n = 7
A/2n:4=16<=>2n:22=24=>2n=24.22=26=>n=6
B/3n:32=243<=>3n:32=35=>3n=35.32=37=>n=7
C/2n-64=2=>2n=64+2=66=>n không tồn tại
