Question

tìm số nguyên x, biết:

n) (-8).x + 17 = -23

o) (-15).x = 10.(-4) - 5

p) (-3).x -4 = 2.(-7) + 4

q) x + x + x + 91 = -2

r) -152 - (3x + 1) = (-2) . (-27)

Answer 1

n: (-8)*x+17=-23

=>\(x\cdot\left(-8\right)=-23-17=-40\)

=>\(x\cdot8=40\)

=>\(x=\dfrac{40}{8}=5\)

o: \(\left(-15\right)\cdot x=10\left(-4\right)-5\)

=>\(x\cdot\left(-15\right)=-40-5=-45\)

=>\(x\cdot15=45\)

=>\(x=\dfrac{45}{15}=3\)

p: \(\left(-3\right)\cdot x-4=2\cdot\left(-7\right)+4\)

=>\(\left(-3\right)\cdot x-4=-14+4=-10\)

=>\(x\left(-3\right)=-10+4=-6\)

=>\(3x=6\)

=>\(x=\dfrac{6}{3}=2\)

q: x+x+x+91=-2

=>\(3x+91=-2\)

=>\(3x=-2-91=-93\)

=>\(x=-\dfrac{93}{3}=-31\)

r: \(-152-\left(3x+1\right)=\left(-2\right)\cdot\left(-27\right)\)

=>\(-152-3x-1=54\)

=>\(-153-3x=54\)

=>\(3x=-153-54=-207\)

=>\(x=-\dfrac{207}{3}=-69\)