a) \(35-3.\left|x\right|=5.\left(2^3-4\right)\)
\(35-3.\left|x\right|=5.\left(8-4\right)\)
\(35-3.\left|x\right|=5-4\)
\(35-3.\left|x\right|=1\)
\(3.\left|x\right|=35-1\)
\(3.\left|x\right|=34\)
\(\left|x\right|=34:3\)
\(\left|x\right|=\frac{34}{3}\)
\(=>x=\frac{34}{3}\)hoặc \(x=-\frac{34}{3}\)
b)\(10+2.\left|x\right|=2.\left(3^2-1\right)\)
\(10+2.\left|x\right|=2.\left(9-1\right)\)
\(10+2.\left|x\right|=2.8\)
\(10+2.\left|x\right|=16\)
\(2.\left|x\right|=16-10\)
\(2.\left|x\right|=6\)
\(\left|x\right|=6:2\)
\(\left|x\right|=3\)
\(=>x=3\)hoặc \(x=-3\)
a)35-3|x|=5(8-4)
35-3|x|=5.4=20
3|x|=35-20=15
|x|=15:3=5
=>x=5 hoặc x=-5
a)
\(35-3|x|=5\left(2^3-4\right)\)
\(\Rightarrow35-3|x|=5\left(8-4\right)\)
\(\Rightarrow35-3|x|=5.4\)
\(\Rightarrow35-3|x|=20\)
\(\Rightarrow3|x|=35-20\)
\(\Rightarrow3|x|=15\)
\(\Rightarrow|x|=15\div3\)
\(\Rightarrow|x|=5\)
\(\Rightarrow\orbr{\begin{cases}x=5\\x=-5\end{cases}}\)
Vậy \(x=5\) hoặc \(x=-5\)
b)
\(10+2|x|=2\left(3^2-1\right)\)
\(\Rightarrow10+2|x|=2\left(9-1\right)\)
\(\Rightarrow10+2|x|=2.8\)
\(\Rightarrow10+2|x|=16\)
\(\Rightarrow2|x|=16-10\)
\(\Rightarrow2|x|=6\)
\(\Rightarrow|x|=6\div2\)
\(\Rightarrow|x|=3\)
\(\Rightarrow\orbr{\begin{cases}x=3\\x=-3\end{cases}}\)
Vậy \(x=3\) hoặc \(x=-3\)
