\(\left|x-m\right|+\left|x^2+4x-5\right|=0\)
\(\hept{\begin{cases}\left|x-m\right|\ge0\\\left|x^2+4x-5\right|\ge0\end{cases}\text{Dấu }=}\text{xảy ra khi}\)
\(\hept{\begin{cases}x-m=0\\x^2+4x-5=0\end{cases}\Rightarrow\hept{\begin{cases}x=m\\x^2+5x-x-5=0\end{cases}\Rightarrow}\hept{\begin{cases}x=m\\\left(x-1\right).\left(x+5\right)=0\end{cases}\Rightarrow}\hept{\begin{cases}x=m\\x_1=1,x_2=-5\end{cases}}}\)
Vậy x=m=1 hoặc x=m=-5