Question

tìm GTNN hoặc GTLN của 

A= 4-x^2+3

C= (x+1)(x+2)(x+3)(x+4)

Answer 1

\(A=4-x^2+3\)

\(=-x^2+7\le7\)

Khi x=0

\(C=\left(x+1\right)\left(x+2\right)\left(x+3\right)\left(x+4\right)\)

\(=\left(x^2+5x+4\right)\left(x^2+5x+6\right)\)

Đặt \(t=x^2+5x+4\) thì

\(=t\left(t+2\right)=t^2+2t+1-1\)

\(=\left(t+1\right)^2-1\ge-1\)

Answer 2

Khi x=0

Đặt  thì

Answer 3

cau sau cua HeroZombie ko dung r!sao lai bo trong v!canh cao day!

Answer 4

Y mk la cai cau bi bo trong ay!