Ta có: \(E=\dfrac{x^2+8}{x^2+2}=\dfrac{x^2+2+6}{x^2+2}=1+\dfrac{6}{x^2+2}\)
Để E đạt GTLN thì \(\dfrac{6}{x^2+2}\) đạt GTLN hay \(x^2+2\) đạt GTNN
mà \(x^2+2\ge2\)\(\Rightarrow\)\((\dfrac{6}{x^2+2})_{max}=\dfrac{6}{2}=3\)
\(\Rightarrow E_{max}=1+3=4\Leftrightarrow x=0\)