Question

Tìm ĐKXĐ

\(\sqrt{\dfrac{x+3}{5-x}}\)

Answer 1

ĐKXĐ: \(\dfrac{x+3}{5-x}>=0\)

=>\(\dfrac{x+3}{x-5}< =0\)

TH1: \(\left\{{}\begin{matrix}x+3>=0\\x-5< 0\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}x>=-3\\x< 5\end{matrix}\right.\)

=>-3<=x<5

TH2: \(\left\{{}\begin{matrix}x+3< =0\\x-5>0\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}x>5\\x< =-3\end{matrix}\right.\)

=>Loại

Vậy: -3<=x<5