Question

Tìm đa thức Q biết: 
( 2x² - y² + 3/4xy ) + Q = x² - 2y² + 3/4xy 
Please help me!!!!!
 

Answer 1

Q= (x² - 2y² + 3/4xy) - (2x² - y² + 3/4xy)

Q = x² - 2y² + 3/4xy - 2x² + y² - 3/4xy

Q= (x² - 2x²) + (-2y² + y²) + (3/4xy - 3/4xy)

Q= -x² - y² 

#Hk_tốt

#Ken'z

Answer 2

\(\left(2x^2-y^2+\frac{3}{4}xy\right)+Q=x^2-2y^2+\frac{3}{4}xy\)

\(\Rightarrow Q=x^2-2y^2+\frac{3}{4}xy-2x^2+y^2-\frac{3}{4}xy\)

\(\Rightarrow Q=-x^2-y^2\)

Vậy \(Q=-x^2-y^2\)