=>\(\dfrac{3}{x-5}-\dfrac{y}{3}=\dfrac{1}{6}\)
=>\(\dfrac{9-y\left(x-5\right)}{3\left(x-5\right)}=\dfrac{1}{6}\)
=>9-y(x-5)=1/2(x-5)
=>(x-5)(1/2+y)=9
=>(x-5)(2y+1)=18
=>\(\left(x-5;2y+1\right)\in\left\{\left(18;1\right);\left(-18;-1\right);\left(2;9\right);\left(-2;-9\right);\left(6;3\right);\left(-6;-3\right)\right\}\)
=>\(\left(x,y\right)\in\left\{\left(23;0\right);\left(-13;-1\right);\left(7;4\right);\left(3;-5\right);\left(11;1\right);\left(-1;-2\right)\right\}\)