Ta có :
\(2^{3x+2}=4^{x+5}\)
\(\Rightarrow2^{3x+2}=\left(2^2\right)^{x+5}\)
\(\Rightarrow2^{3x+2}=2^{2x+10}\)
\(\Rightarrow3x+2=2x+10\)
\(\Rightarrow3x-2x=10-2\)
\(\Rightarrow x=8\)
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Ta có: 2^3x+2=4^x+5
2^3x+2=2^(2x+5)
2^3x+2=2^2x+10
3x+2=2x+10
3x-2x=10-2
x=8
Vậy x=8
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