Question

 Tìm    3^2 ( x + 1 ) - 3 = 2^3 + ( 7^2 * 2 ) : 14 

Answer 1

3²(x+1)-3=2³+(7².2):14

9.(x+1)-3=8+(49.2):14

9.(x+1)-3=8+98:14

9.(x+1)=8+7+3

9.(x+1)=18

x+1=18:9=2

x=2-1=1

vậy x=1

Answer 2

\(3^2\left(x+1\right)-3=2^3+\left(7^2\cdot2\right):14\)

\(9\left(x+1\right)-3=8+98:14\)

\(9x+9-3=8+7\)\(\)

\(9x=8+7+3-9\)

\(9x=9\)

\(x=9:9=1\)

Vậy x = 1

Answer 3

Ta có: \(3^2\left(x+1\right)-3=2^3+\left(7^2\cdot2\right):14\)

\(\Leftrightarrow9\left(x+1\right)=8+7+3=18\)

\(\Leftrightarrow x+1=2\)

hay x=1