\(i,=29-\left(16+3.2\right)\\ =29-\left(16+6\right)\\ =29-22\\ =7\\ j,=5.4+98:49\\ =20+2\\ =22\\ k,=3^2-147:49\\ =9-3\\ =6\)
i) 29- [16 + 3.(51-49)]
= 29 - [16 + 3. 2]
=29 - [16 + 6]
=29 - 22
=7
j) 5.2 mũ 2 + 98 : 7 mũ 2
=5. 4 + 98 : 49
= 20 + 2
= 22
k) 3 mũ 11 : 3 mũ 9 - 147 : 7 mũ 2
=177147 : 19683 - 147 : 49
= 9 - 3
= 6