b: Ta có: \(7^5:49-5^2\)
\(=7^5:7^2-25\)
=343-25
=318
c: Ta có: \(4\cdot5^5:125\)
\(=4\cdot5^5:5^3\)
\(=4\cdot5^2=100\)
a. \(3^3.2^2-4^2=9.4-4^2=4\left(9-4\right)=4.5=20\)
b. \(7^5:49-5^2=7^5:7^2-5^2=7^3-5^2=343-25=318\)
c. \(4.5^5:125=4.5^5:5^3=4.5^2=4.25=100\)
d. \(1024:\left(32.2^5\right)=2^{10}:\left(2^5.2^5\right)=2^{10}:2^{10}=1\)
e. \(\left(5^7+5^6+5^5\right):5^5=5^5\left(5^2+5+1\right):5^5=5^2+5+1=31\)
f. \(\left(5^{2019}-5^{2018}\right):5^{2018}=5^{2018}\left(5-1\right):5^{2018}=5-1=4\)
a. 33 . 22 - 42
= 27 . 4 - 16
= 108 - 16
= 92
b. 75 : 49 - 52
= 16807 : 49 - 25
= 343 - 25
= 318
c. 4 . 55 : 125
= 4 . 3125 : 125
= 12500 : 125
= 100
d. 1024 : (32 . 25)
= 1024 : (32 . 32)
= 1024 : 1024
= 1
e. (57 + 56 + 55) : 55
= (78125 + 15625 + 3125) : 3125
= 25 + 5 + 1
= 31
f. (52019 - 52018) : 52018
= (52019 : 52018) - (52018 : 52018)
= 52019 - 2018 - 52018 - 2018
= 5 - 1
= 4
a: Ta có: \(3^3\cdot2^2-4^2\)
\(=27\cdot4-16\)
=108-16
=92
d: Ta có: \(1024:\left(32\cdot2^5\right)\)
\(=\dfrac{2^{10}}{2^5\cdot2^5}\)
=1
e: Ta có: \(\left(5^7+5^6+5^5\right):5^5\)
\(=5^2+5+1\)
=25+5+1
=31
f: Ta có: \(\left(5^{2019}-5^{2018}\right):5^{2018}\)
=5-1
=4
