d: Ta có: \(5\sqrt{20}-3\sqrt{12}+15\cdot\sqrt{\dfrac{1}{5}}-4\sqrt{27}+\sqrt{\sqrt{5^2-4^2}}\)
\(=10\sqrt{5}-6\sqrt{3}+3\sqrt{5}-12\sqrt{3}+\sqrt{3}\)
\(=-17\sqrt{3}+13\sqrt{5}\)
e: Ta có: \(\sqrt{7+4\sqrt{3}}+\sqrt{28-10\sqrt{3}}\)
\(=2+\sqrt{3}+5-\sqrt{3}\)
=7
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