\(-\frac{3}{7}.\frac{5}{9}+\frac{4}{9}.\frac{-3}{7}+2.\frac{3}{7}\)\(=\frac{3}{7}\left(-\frac{5}{9}-\frac{4}{9}+2\right)=\frac{3}{7}\left(-1+2\right)=\frac{3}{7}\)
so sánh: \(\frac{21}{-42}=\frac{1}{-2}=\frac{2}{-4}\); vì \(\frac{2}{-4}>\frac{3}{-4}\)nên \(\frac{21}{-42}>\frac{3}{-4}\)
tìm x: a) \(x-\frac{2}{5}=\frac{1}{10}\)
\(\Rightarrow x=\frac{1}{10}+\frac{2}{5}=\frac{1}{10}+\frac{4}{10}=\frac{5}{10}=\frac{1}{2}\)
b) \(\frac{4}{6}+\frac{5}{4}x=\frac{7}{6}\)
\(\Rightarrow\frac{5}{4}x=\frac{3}{6}=\frac{1}{2}\)
\(\Rightarrow x=\frac{2}{5}\)