Question

Thực hiện phép chia:                                        (chia đa thức - đơn thức)
\(-\dfrac{1}{3}\)x⁵y² : (-2xy)-(x²+2x+1) : (x+1)

Answer 1

`-1/3x^5y^2:(-2xy)-(x^2+2x+1):(x+1)`

`=-1/3:(-2).(x^5:x).(y^2:y)-(x+1)^2:(x+1)`

`=-1/6x^4y-(x+1)`

`=-1/6x^4y-x-1`

Answer 2

\(\dfrac{-1}{3}x^5y^2:\left(-2xy\right)-\left(x^2+2x+1\right):\left(x+1\right)\)

\(=\dfrac{1}{6}x^4y-x-1\)