Question

Thực hiện các phép tính sau:

\(\dfrac{2}{\sqrt{6}-2}+\dfrac{2}{\sqrt{6}+2}+\dfrac{5}{\sqrt{6}}\)

Answer 1

\(\dfrac{2}{\sqrt[]{6}-2}+\dfrac{2}{\sqrt[]{6}+2}+\dfrac{5}{\sqrt[]{6}}\)

\(=\dfrac{2}{\sqrt[]{6}-2}+\dfrac{2}{\sqrt[]{6}+2}+\dfrac{5\sqrt[]{6}}{6}\)

\(=\dfrac{12\left(\sqrt[]{6}+2\right)}{6\left(\sqrt[]{6}-2\right)\left(\sqrt[]{6}+2\right)}+\dfrac{12\left(\sqrt[]{6}-2\right)}{6\left(\sqrt[]{6}-2\right)\left(\sqrt[]{6}+2\right)}+\dfrac{5\sqrt[]{6}\left(\sqrt[]{6}-2\right)\left(\sqrt[]{6}+2\right)}{6\left(\sqrt[]{6}-2\right)\left(\sqrt[]{6}+2\right)}\)

\(=\dfrac{12\sqrt[]{6}+24+12\sqrt[]{6}-24+5\sqrt[]{6}\left(6-2\right)}{6\left(6-2\right)}\)

\(=\dfrac{24\sqrt[]{6}+20\sqrt[]{6}}{24}\)

\(=\dfrac{44\sqrt[]{6}}{24}\)

\(=\dfrac{11\sqrt[]{6}}{6}\)

Answer 2

bài này mà cx đi hỏi má