Question

tách cái này theo cách thêm bớt như nào nhỉ mấy bn

\(x+2\sqrt{x}-3\)

Answer 1

\(x+2\sqrt{x}-3\\ =x-\sqrt{x}+3\sqrt{x}-3\\ =\sqrt{x}\left(\sqrt{x}-1\right)+3\left(\sqrt{x}-1\right)\\ =\left(\sqrt{x}-1\right)\left(\sqrt{x}+3\right)\)

Answer 2

ĐKXĐ: \(x\ge0\)

\(x+2\sqrt{x}-3=x-\sqrt{x}+3\sqrt{x}-3=\sqrt{x}\left(\sqrt{x}-1\right)+3\left(\sqrt{x}-1\right)\)

\(=\left(\sqrt{x}+3\right)\left(\sqrt{x}-1\right)\)