\(\left[-\sqrt{2,25}+4\sqrt{\left(-2,15\right)^2}-\left(3\sqrt{\dfrac{7}{6}}\right)^2\right]\sqrt{1\dfrac{9}{16}}\)
Tìm \(x\in Q\), biết:
\(a,\left|x+\dfrac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
tìm x biết
\(\left|x+\frac{14}{15}\right|-\left|x-3,75\right|=-\left|-2,15\right|\)
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
M.n giup em vs mai em nop r em cam on
Tìm x,biết:
1.\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)
2. \(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
3. \(\left|4.x\right|-\left|-13.5\right|=\left|2\frac{1}{4}\right|\)
Nhanh hộ em với ạ !!
Tính:
a) \(\sqrt{\left(-5\right)^2}+\sqrt{5^2}-\sqrt{\left(-3\right)^2}-\sqrt{3^2}-\left(\sqrt{7}\right)^2\)
b) \(\left[\sqrt{4^2}\right]+\sqrt{\left(-4\right)^2}.\left(\sqrt{5}\right)^2-\sqrt{5^{-2}}\)
c) \(\sqrt{\left(-10\right)^2}+10.\left(-\sqrt{5}\right)^2\)
HỘ MK BÀI NÀY NHA MỌI NGƯỜI
Thự hiện phép tính:
\(\left(\left(2\sqrt{2}\right)^2:2,4\right).\left(5,25:\left(\sqrt{7}\right)^2\right):\left(\left(2\frac{1}{7}:\frac{\left(\sqrt{5}\right)^2}{7}\right):2^2.\frac{\left(2.\sqrt{2}\right)}{\sqrt{81}}^2\right)\)
tính
\(\left\{\left[\left(2\sqrt{2}\right)^2:2,4\right].\left[5,25:\left(\sqrt{7}\right)^2\right]\right\}:\left\{\left[2\frac{1}{7}:\frac{\left(\sqrt{5}\right)^2}{7}\right]:\left[2^3:\frac{\left(2\sqrt{2}\right)^2}{\sqrt{81}}\right]\right\}\)
tìm x,y,x
\(\sqrt{\left(x-\sqrt{2}\right)^2}+\sqrt{\left(y+\sqrt{2}\right)^2}+\left|x+y+z\right|=0\)
so sánh A và B:
\(A=\sqrt{225}-\frac{1}{\sqrt{5}}-1\) \(B=\sqrt{196}-\frac{1}{\sqrt{6}}\)
ai giải đc câu nào thì giải giúp với
Giúp mik với
Tính
a)\(\frac{2}{3}\sqrt{81}-\left(\frac{-3}{4}\right).\sqrt{\frac{9}{64}}+\left(\frac{\sqrt{2}}{3}\right)^2\)
b)\(\left(-\sqrt{\frac{5}{4}}\right)^2-\sqrt{\frac{9}{4}}:\left(-4,5\right)-\sqrt{\frac{25}{16}}.\sqrt{\frac{64}{9}}\)
c)\(-2^4-\left(-2\right)^2:\left(-\sqrt{\frac{16}{121}}\right)-\left(-\sqrt{\frac{2}{3}}\right)^2:\left(-2\frac{2}{3}\right)\)