\(\sqrt{23-8\sqrt{7}}=\sqrt{\left(\sqrt{16}-\sqrt{7}\right)^2}=\sqrt{16}-\sqrt{7}=4-\sqrt{7}\)
\(\sqrt{23-8\sqrt{7}}=4-\sqrt{7}\)
\(\sqrt{23-8\sqrt{7}}=\sqrt{\left(\sqrt{16}-\sqrt{7}\right)^2}=\sqrt{16}-\sqrt{7}=4-\sqrt{7}\)
\(\sqrt{23-8\sqrt{7}}=4-\sqrt{7}\)
rút gọn biểu thức:
\(\sqrt{8-2\sqrt{7}}-\sqrt{23-8\sqrt{7}}\)
\(\dfrac{\sqrt{3-\sqrt{5}}\left(3+\sqrt{5}\right)}{\sqrt{10}+\sqrt{2}}\)
\(\dfrac{10+2\sqrt{10}}{\sqrt{5}+\sqrt{2}}\)+\(\dfrac{8}{1-\sqrt{5}}\)
\(\dfrac{5+\sqrt{7}}{9-\sqrt{23+8\sqrt{7}}}\)+\(\dfrac{5-\sqrt{7}}{2+\sqrt{16+6\sqrt{7}}}\)
\(\dfrac{1}{\sqrt{2}+\sqrt{2+\sqrt{3}}}\)+\(\dfrac{1}{\sqrt{2}-\sqrt{2+\sqrt{3}}}\)
Rút gọn: \(\sqrt{23+8\sqrt{7}}-\sqrt{7}\)
giải gấp giúp e nha
cmr
\(\sqrt{23+8\sqrt{7}}-\sqrt{7}=4\)
Chứng minh đẳng thức
\(\left(4-\sqrt{7}\right)^2=23-8\sqrt{7}\)
\(\sqrt{9-4\sqrt{5}}-\sqrt{5}=-2\)
\(\dfrac{\sqrt{4-2\sqrt{3}}}{1+\sqrt{2}}:\dfrac{\sqrt{2}-1}{\sqrt{3}+1}=2\)
\(\left(\dfrac{2\sqrt{3}-\sqrt{6}}{\sqrt{8}-2}-\dfrac{\sqrt{216}}{3}\right).\dfrac{1}{\sqrt{6}}=-1,5\)
Chứng minh đẳng thức
\(\left(4-\sqrt{7}\right)^2=23-8\sqrt{7}\)
\(\sqrt{9-4\sqrt{5}}-\sqrt{5}=-2\)
\(\dfrac{\sqrt{4-2\sqrt{3}}}{1+\sqrt{2}}:\dfrac{\sqrt{2}-1}{\sqrt{3}-1}=2\)
\(\left(\dfrac{2\sqrt{3}-\sqrt{6}}{\sqrt{8}-2}-\dfrac{\sqrt{216}}{3}\right).\dfrac{1}{\sqrt{6}}=-1,5\)
Rút gọn:
D=\(\sqrt{11-6\sqrt{2}}-3+\sqrt{2}\)
E=\(\sqrt{23+8\sqrt{7}}-\sqrt{7}\)
Chứng minh đẳng thức:
\(\sqrt{9-4\sqrt{5}}-\sqrt{5}=-2\)
\(\sqrt{23+8\sqrt{7}}-\sqrt{7=4}\)
Rút gọn
\(\sqrt{23+8\sqrt{7}}\)