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10 + \(2\sqrt{\left(2-x^2\right)\left(x^2+8\right)}\)= 16
<=> - x4 - 6x2 + 16 = 9
<=> (x2 - 1)(x2 + 7) = 0
<=> x = (1; -1)
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Các câu hỏi tương tự
a) 8sqrt{x+2} + sqrt{11-x} - 2sqrt{22+9x-x^2}+ 4 0b) sqrt{1+4x}+ 2sqrt{2-x}+2sqrt{left(1+4xright)left(2-xright)}3c) sqrt{8+sqrt{x}}+sqrt{5-sqrt{x}}5d) sqrt{x^4-1}-2 sqrt{x-1}- 2sqrt{x^3+x^2+x+1}
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a) \(8\sqrt{x+2}\) + \(\sqrt{11-x}\) - \(2\sqrt{22+9x-x^2}\)+ 4 =0
b) \(\sqrt{1+4x}\)+ \(2\sqrt{2-x}\)+\(2\sqrt{\left(1+4x\right)\left(2-x\right)}\)=3
c) \(\sqrt{8+\sqrt{x}}\)+\(\sqrt{5-\sqrt{x}}\)=5
d) \(\sqrt{x^4-1}\)-2 =\(\sqrt{x-1}\)- \(2\sqrt{x^3+x^2+x+1}\)
1\(\sqrt{5+2\sqrt{8}}-\sqrt{5-2\sqrt{8}}\) 2)\(\dfrac{\sqrt{x^2+2\sqrt{3x}+3}}{x^2-3}\) 3) \(\dfrac{\sqrt{x^2-5x+6}}{\sqrt{x-2}}\) 4)\(\dfrac{\sqrt{\left(x-4\right)^2}}{x^2-5x+4}\) 5) \(\dfrac{3x+1}{\sqrt{9x^2+6x+1}}\)
\(\left(5\right)\sqrt{x+3-4\sqrt{x-1}}\sqrt{x+8+6\sqrt{x-1}}=5\)
\(\left(6\right)2x^2+3x+\sqrt{2x^2+3x+9}=33\)
\(\left(7\right)\sqrt{3x^2+6x+12}+\sqrt{5x^4-10x^2+30}=8\)
\(\left(8\right)x+y+z+8=2\sqrt{x-1}+4\sqrt{y-2}+6\sqrt{z-3}\)
1) x-\(7\sqrt{x-3}\) -9=0 2) \(\sqrt{x+3}\) =5-\(\sqrt{x-2}\) 3) \(\sqrt{x-4\sqrt{x+4}}\) =3 4) \(\sqrt{8-\dfrac{2}{3}x}-5\sqrt{2}\) =0 5) \(\sqrt{x^2-4x+4}\) =2-x
\(\left(6\right)\dfrac{3\sqrt{x}}{5\sqrt{x}-1}\le-3\)
\(\left(7\right)\dfrac{8\sqrt{x}+8}{6\sqrt{x}+9}>\dfrac{8}{3}\)
\(\left(8\right)\dfrac{\sqrt{x}-2}{2\sqrt{x}-3}< -4\)
\(\left(9\right)\dfrac{4\sqrt{x}+6}{5\sqrt{x}+7}\le-\dfrac{2}{3}\)
\(\left(10\right)\dfrac{6\sqrt{x}-2}{7\sqrt{x}-1}>-6\)
a)\(\sqrt{3x-1}=2\) c) \(\sqrt{x^2-4x+4}=3x-1\)
b)\(\sqrt{x+}=2-x\) d)\(\sqrt{x^2+4}=\sqrt{3x+8}\)
Tìm điều kiện có nghĩa:1) sqrt{2x^2}2) sqrt{-x}3) sqrt{-x^2-3}4) sqrt{x^2+2x+3}5) sqrt{-a^2+8a-16}6) sqrt[]{16x^2-25}7) sqrt{4x^2-49}8) sqrt{8-x^2}9) sqrt{x^2-12}10) sqrt{x^2+2x-3}11) sqrt{2x^2+5x+3}12) sqrt{dfrac{4}{x-1}}13) sqrt{dfrac{-1}{x-3}}14) sqrt{dfrac{-3}{x+2}}15) sqrt{dfrac{1}{2a-1}}16) sqrt{dfrac{2}{3-2a}}17) sqrt{dfrac{-1}{2a-5}}18) sqrt{dfrac{-2}{3-5a}}19) sqrt{dfrac{-a}{5}}20) dfrac{1}{sqrt{-3a}}
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Tìm điều kiện có nghĩa:
1) \(\sqrt{2x^2}\)
2) \(\sqrt{-x}\)
3) \(\sqrt{-x^2-3}\)
4) \(\sqrt{x^2+2x+3}\)
5) \(\sqrt{-a^2+8a-16}\)
6) \(\sqrt[]{16x^2-25}\)
7) \(\sqrt{4x^2-49}\)
8) \(\sqrt{8-x^2}\)
9) \(\sqrt{x^2-12}\)
10) \(\sqrt{x^2+2x-3}\)
11) \(\sqrt{2x^2+5x+3}\)
12) \(\sqrt{\dfrac{4}{x-1}}\)
13) \(\sqrt{\dfrac{-1}{x-3}}\)
14) \(\sqrt{\dfrac{-3}{x+2}}\)
15) \(\sqrt{\dfrac{1}{2a-1}}\)
16) \(\sqrt{\dfrac{2}{3-2a}}\)
17) \(\sqrt{\dfrac{-1}{2a-5}}\)
18) \(\sqrt{\dfrac{-2}{3-5a}}\)
19) \(\sqrt{\dfrac{-a}{5}}\)
20) \(\dfrac{1}{\sqrt{-3a}}\)
Giải phương trình:
a. \(\sqrt{x^2-4}-x^2+4=0\)
b. \(\sqrt{x^2-4x+5}+\sqrt{x^2-4x+8}+\sqrt{x^2-4x+9}=3+\sqrt{5}\)
c. \(\sqrt{2-x^2+2x}+\sqrt{-x^2-6x-8}=1+\sqrt{3}\)
d. \(\sqrt{9x^2+6x+2}+\sqrt{45x^2-30x+9}=\sqrt{6x-9x^2+8}\)
Rút gọn
a)\(\sqrt{m+2\sqrt{m-1}}-\sqrt{m-2\sqrt{m-1}}\left(m>2\right)\)
b)\(\sqrt{x-1-2\sqrt{x-2}}+\sqrt{\sqrt{x-1+2\sqrt{x-2}}}\)
c)\(\sqrt{x+3+4\sqrt{x-1}}+\sqrt{x+8-8\sqrt{x-1}}\left(1< x< 10\right)\)
d)\(\sqrt{2m+4+6\sqrt{2m-5}}+\sqrt{2m-4-2\sqrt{2m-5}}\)
Aleft(dfrac{xsqrt{x}-1}{x-sqrt{x}}-dfrac{xsqrt{x}+1}{x+sqrt{x}}right):dfrac{x-2sqrt{x}+1}{x-1} ( ĐKXĐ x0;x≠4)Pleft(dfrac{3sqrt{x}}{sqrt{x}+2}+dfrac{sqrt{x}}{2-sqrt{x}}+dfrac{8sqrt{x}}{x-4}right):left(2-dfrac{2sqrt{x}+3}{sqrt{x}+2}right) Eleft(1-dfrac{sqrt{x}}{sqrt{x}+1}right):left(dfrac{sqrt{x}+2}{sqrt{x}+3}+dfrac{sqrt{x}-3}{2-sqrt{x}}+dfrac{sqrt{x}-2}{x+sqrt{x}-6}right) (ĐKXĐ x≥0;x≠4)RÚT GỌN GIÚP MÌNH VỚI A
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A=\(\left(\dfrac{x\sqrt{x}-1}{x-\sqrt{x}}-\dfrac{x\sqrt{x}+1}{x+\sqrt{x}}\right):\dfrac{x-2\sqrt{x}+1}{x-1}\) ( ĐKXĐ x>0;x≠4)
P=\(\left(\dfrac{3\sqrt{x}}{\sqrt{x}+2}+\dfrac{\sqrt{x}}{2-\sqrt{x}}+\dfrac{8\sqrt{x}}{x-4}\right):\left(2-\dfrac{2\sqrt{x}+3}{\sqrt{x}+2}\right)\)
E=\(\left(1-\dfrac{\sqrt{x}}{\sqrt{x}+1}\right):\left(\dfrac{\sqrt{x}+2}{\sqrt{x}+3}+\dfrac{\sqrt{x}-3}{2-\sqrt{x}}+\dfrac{\sqrt{x}-2}{x+\sqrt{x}-6}\right)\) (ĐKXĐ x≥0;x≠4)
RÚT GỌN GIÚP MÌNH VỚI A